Poker Odds Calculator TournamentIndicator

admin answers:

I don’t need to look at the flash cards to give you my answer.

To play PERFECT Basic Strategy, you need to adjust your strategy to the casino’s rules. In other words, what two cards you double down on are going to be different at casinos where the rule is the Dealer must STAND on soft-17 and the casinos where the rule is the Dealer must HIT soft-17.

Below is the Basic Strategy Calculator from the Wizard of Odds. Near the top, you can enter the specific rules of any specific casino. Notice that every time you change a rule, the listed strategy changes just slightly for certain scenarios.

This guy is the best. (I have absolutely nothing to do with this website, by the way. I only wish I were this smart!) All of his suggestions for Basic Strategy are based on mathematics and millions of simulations of hands.

Figure out the rules for your casino, check your flash cards against the Wizard of Odds‘ strategy charts, and adjust your flash cards accordingly.

***EDIT***

Aw crap. It just occurred to me that you’re looking for deviations based on the count. Well that was a complete waste of time. Sorry! I’ll leave my response just in case you haven’t seen the Wizard of Odds calculator. Sorry again.

Then again, even when considering your specific question regarding deviations from the count, it still would be reliant on the rules of specific casinos.

admin answers:

There is a handy odds calculator at http://www.betstarter.com/lottery/LottoOdds.asp
Just enter 7 and 33 in the two boxes and the following results will be displayed:

7-of-7 = 1 : 4,272,048.0
6-of-7 = 1 : 23,472.8
5-of-7 = 1 : 625.9
4-of-7 = 1 : 46.9
3-of-7 = 1 : 8.2
2-of-7 = 1 : 3.1
1-of-7 = 1 : 2.7

admin answers:

Edit — nevermind, it’s simpler than what I was talking about. You’re asking about rolling exact numbers.

I’ll just do one of them, since it’s essentially the same problem asked 6 times. So let’s figure out the odds of rolling a sum of 14.

First we need to know how many ways there are to roll it.

A) 9 dice can be 1’s and 1 die can be a 5.
B) 8 dice can be 1’s and 2 dice can be 3’s
c) 8 dice can be 1’s, 1 die can be a 4, 1 die can be a 2
d) 7 dice can be 1’s, 2 dice can be 2’s and 1 die can be a 3.
E) 6 dice can be 1’s and 4 dice can be 2’s.

There are 10 ways for A to happen.
There are 10C2 = 45 ways for B to happen.
There are 10*9 = 90 ways for C
There are 10*(9C2) = 360 ways for D to happen.
There are 10C4 = 210 ways for E to happen.

In total there are 715 ways to roll a 14. There are 10^10 possible rolls.

Probability = 715 / 10^10 = 143 / 2 billion = about 1 in 13,986,014 chance
(Aka, very hard to do!)

The easy way to arrive at 715 is to use this calculator — http://www.btinternet.com/~se16/js/partitions.htm

Select „compositions of“: 14
„Exact number of terms“: 10
„Each term no more than“: 6

You can do the same with any sum, and then divide the answer by 10^10 for the probability. For a „1 in __“ answer, flip the numerator and denominator. I used WolframAlpha calculator: http://www.wolframalpha.com/input/?i=715%2F%2810^10%29

admin answers:

I just looked at the manual, and this isn’t a symbolic calculator. The „integration“ it does is a numerical approximation of a definite integral…and you can estimate a derivative manually by computing:

f'(x) ~= [f(x + h) – f(x)] / h

for a given value of x and some small value of h. It looks like that’s the best you’re going to get. It’s odd that they didn’t add that to the firmware, since the integral operation already knows how to input a function definition. A numerical derivative operation could do the same.

admin answers:

If function even
f(-x)=f(x)
has symmetric about the y-axix

if function odd
f(-x)=-f(x)
has point symmetry about the origin(180 degrees)

neither means neither even or odd

A) f(x)= cube root (7x^3 – 3x)

let’s first see if it’s even
sub -x instead of x
f(-x)=cube root (-7x^3 + 3x)
:. F(x) not = f(-x)
:. Not even

let’s see if it is odd
factor out – 1st
-f(x)= cube root (-7x^3 + 3x)
sub -x instead of x
f(-x)=cube root (-7x^3 + 3x)

:.-f(x)=f(-x)
:. It’s an odd function

B) f(x)= square root (4x^5 + 7x^3)

let’s first see if it’s even
sub -x instead of x
f(-x)=square root (-4x^5 – 7x^3)
:.f(x) not=f(-x)
:. Not even function

let’s see if it is odd
factor out – 1st
-f(x)=square root (-4x^5 – 7x^3)
-f(x)=DNE
sub -x instead of x
f(-x)=square root (-4x^5 – 7x^3)
f(-x)=DNE

bc under (1/2) answer can not be –

:.f(x) not=f(-x)
:.not Odd function

:. Neither

By the use of graphmatica or graphing calculator u can verify ur answers