Poker Odds Calculator TournamentIndicator

admin answers:

Odds and probability are not the same. They are related but not the same. While the probability of getting a tail on one toss of a fair coin is 1/2, the odds for getting a tail on one toss of a fair coin is 1:1 (read as one to one).

The probability of the random number generator selecting 99 on the first pick is 1/100 where 1 represents the number of 99s on the die (just one 99) and 100 represents the number of possible outcomes of tossing the die. (Die is the singular of dice –> one of a pair of dice.)

Because the die tosses are independent (the outcome of the first toss does not affect the outcome of the second toss), the probability of the second, third, and fourth consecutive tosses being a 99 are each 1/100.

Therefore the probability of 4 consective tosses of „99“ would be 1/100 time 1/100 times 1/100 times 1/100 or 1/100000000 = .00000001

admin answers:

Dice are a, b, c

Instead of calling each die as 1,2,3,4,5,6, we can simply call it as even or odd with 50% probability.

That reduces it to 8 possible cases, each with 1/8 probability of occurring:

a even, b even, c even = total even
a even, b even, c odd = total odd
a even, b odd, c even = total odd
a odd, b even, c even = total odd
a odd, b odd, c even = total even
a odd, b even, c odd = total even
a even, b odd, c odd = total even
a odd, b odd, c odd = total odd

so 4/8 odd, and 4/8 even.

Or, a 50/50 shot of each

admin answers:

If order matters it’s a permutation.
(10 runners in a race, how many way to give gold, silver, bronze? 10 P 3)
If order doesn’t matter, it’s a combination.
(10 runners in a race, how many ways to hand out 3 medals? 10 C 3)

Theoretical Probability: what you can calculate
Experimental Probability: what actually happens.

For example, if you flip a coin 4 times, there is 1/16 chance of getting heads 4 times in a row.
If you actually flip a coin 4 times, and do *that* 160 times,
you might get 4 heads 8 or 9 or 10 or 11 or 12 or some other number of times.

The calculating 1/16 probability is Theoretical.
Actually flipping the coin and toting up the results is experimental.
If it only came heads 4 times in a row on 8 of the trials,
the experimental probability would be 1/20 (8 / 160) instead of the Theoretical (1/16).

If you did the experiment 1.6 million times instead of 160,
you’d expect the Experimental to be very close to the theoretical.

10 people in a race:
10 possibilities for 1st, 9 for 2nd, 8 for 3rd, etc:
10! = permutations

The fruit problem is also permutations since the word „then“ is in there.
Had it been „a plum AND a peach“ that would be combinations.

Probability is 4 plums / 12 fruits followed by (times) 5 peaches / 11 remaining fruits.
4 / 12 * 5 / 11 = 5/33

(If it were combinations, then you’d add the „peach, then plum“ probability,
which, not coincidentally, is the same.)

There are 8 numbers on the die, you are concerned with 2 of them: 2 / 8 = 1/4

Odds is a slightly different way of expressing probability
(and in common usage, the term „odds“ is – incorrectly – used to mean probability,
as in „What are the odds of that happening?“)

Probability is (chosen outcome) / (all outcomes).
For instance, with your die problem:
(2 chosen outcomes [3 and 4]) / (8 total [1 through 8]) = 2 / 8

There are 2 chosen outcomes and 6 others.

Odds in favor is chosen : other.
Odds against is other : chosen.

So for this problem, the odds for are 2 to 6 (or 2 : 6).
And the odds against are 6 to 2 (or 6 : 2).

Of course those can be reduced to „1 to 3“ or „3 to 1“

admin answers:

What are the odds of pulling all those cards out in order?

There’s your answer:: Highly unlikely.

admin answers:

You have to add up all the results you get when you enter 3, 4 and 5. So enter 3 for number of successes, then add your result to what you get when you enter 4, then add that again to what you get when you enter 5 and that is your answer.