Your Questions About Odd Calculator

Maria asks…

A question for those who use ovulation calculators?

I use the one on that uses the dates of the beginning of your last three menstrual cycles to calculate approximately when you will be ovulating next. When I put in my three dates, it gave me a highest fertility date of 5/14 to 5/19.

If I were to have unprotected sex today, and that calculator was correct, could the sperm live to meet the egg and cause pregnancy?

Just looking for opinions out of curiousity. Thanks.

admin answers:

It COULD, but it’s really hard to time everything just right. The sperm would HAVE to live 72 hours, at least, and that’s not always highly likely, and you would HAVE to ovulate on the 14th, which is impossible to predict. You can try, but the odds are just as good as any other time a healthy man and woman have sex – about 20%-25%.

Sharon asks…

What is the fastest, easiest and legal way to make a million dollars cash in one year?

admin answers:

I disagree with j_con999.
You need to have a relative with a Estate of at least $1,000,000.00 and most people don’t have a rich relative.

I disagree with sunflowerr
In fact, winning the lottery is by far the hardest way to make $1,000,000.00
You can verify it using the Lottery Odds Calculator

I disagree with connelly198133
If an exotic dancer gets a $1.00 Bill every minute it will get only $60.00 per hour and even if she worked 16 hours every day she would only get $960.00 per day which after a year is not even close to $365,000.00
Also keep in mind Exotic Dancers HAVE TO PAY the club owner for every hour they work there.
It is impossible to work for 16 hours because Exotic Dancers are only allowed to work for a few hours to keep the patrons happy. If the same exotic dancer was was all day long everybody would get bored and leave. And even if you worked at 4 Clubs every day you would still have to reduce the time it takes to get to each club.
Have you ever seem an exotic dancer leaving a club and drive his own Mercedes Benz?
This job is not a well paid job. There are too many pretty girls without college degrees.

The easiest way to make $1,000,000.00 USD legally asuming you have at least $100,000.00 to start at the beginning of the year would be to hire a Profesional Portfolio Manager with over a decade of experience in the Stock Market to invest your money.
Asuming he daytrades on margin everyday up to $400,000.00 he would only need to make a return on your investment of 250% after a year to make $1,000,000.00

Keep in mind this strategy means also you are willing to risk your entire $100,000.00

A more prudent approach would be to start with $250,000.00 and daytrade on margin everyday up to $500,000.00 and you would need to make a return on your investment of only 100% after a year and you would risk only up tp 50% of your initial investment.

If you cannot risk 50% of your investment you can lower your risk to just 25% but then you would have to increase your time period to at least 2 years.

Also if you don’t have $250,000.00 to start you could increase your time period to at least 2 years (If you have $125,000.00) or 4 years (If you have $62,500.00)

Making a Million Dollars is very easy and you can keep your risk as low as 10% however, if you don’t have too much money to start, it would take a long time.

It really does not matter if you make $1,000,000.00 in one year or in a decade or in half a century as long as you make it.

Most people die without $100,000.00

There are only 7,500,000 millionaires (As of 2004) in the United States of America (Excluding Primary Residence)

35% Percent are retired
36% Are Business Owners.

If you want to know when will you be a millionaire click here:

If you want more detailed information about how to make your first million dollars faster, easier and legally you can drop me a line.

Top 3 Answerer in Business & Finance. (Vote for me)

Thomas asks…

The product of the zeros of f(x) = x^3-3x^2-13x+5 is what?

I’ve tried synthetic division, and none of the possibilities (-5,-1,1,5) work. How else can I determine the zeros without using a graphing calculator?

Someone suggested I repost this in the math section.

admin answers:

If you are asking for the product of the zeros, for any polynomial, the product of the zeros is ±(the constant) ÷ (the leading coefficient) (+ if even degree, – if odd degree)

Since your polynomial is a cubic, that would be:
-(5) ÷ (1) = -5.

Daniel asks…

One of my rats is acting agressively toward his brother?

I have two brother rats, they were fine when they were younger, now one attacks the other. They are around 8 months.At first they would play, and I know they need to wrestle for dominanace because they’re young, but now it’s getting a little more serious. I already had to deal with it last year with two adult brother rats, and it ended in one of them having to be put down because of his agression. I just want to know if anyone has any advice on calming the dominant one down?

admin answers:

The first thing to look at is how you’re housing them and their overall health. Being confined to too small of a cage can cause stress and aggression. Double check the size of your cage against the rat cage calculator. Remember that more space is always better, particularly with boys!

Also, have they been to the vet for a check up lately? Illness or pain can cause aggression, it can also lead to the healthier rat picking on the ill one. Parasites (like mites or lice) can be uncomfortable and make the rats irritable as well. A vet check can make sure that there are no physical problems leading to the aggression.

Finally, neutering can be an option. It does reduce aggression in some rats. If performed by an experienced vet it is an easy procedure that they recover from quite quickly. My guy was sleepy the day of the surgery and then upset about being confined for the next two weeks. He just wanted to run and play and was very impatient with me.

Michael asks…

A continuous function which is not uniformly continuous?

I am learning continuity and uniform continuity now, but I’m so confused with this two concepts.

I know the difference of their definitions, so please don’t just tell me how to prove a function is continuous or uniformly continuous. What I don’t understand is that why the hell we need to distinguish uniformly continuous functions from continuous functions. What are their meanings in „real life“?

admin answers:

I assume that you are mostly interested in functions where the input and output are both real numbers, and the domain is an interval. (I’m only going to talk about those functions in my answer.)

You’re probably familiar with the idea that continuous functions are supposed to have graphs without jumps–that is, graphs that you can draw without lifting your pen from the paper.

Uniform continuity means the same thing as continuity, plus one additional condition: There must not be a situation where the value of the function is changing ever more and more rapidly as you move towards the edge of the domain.

To understand why a function could fail to be uniformly continuous, let’s look at a specific function. The function f: (0, ∞) -> R defined by f(x) = sin (1/x) is a good one. This function is continuous on (0, ∞), but not uniformly continuous.

You should graph it on a graphing calculator to get a sense for what the graph looks like. Or use Wolfram Alpha: (Remember that I’m only considering x > 0, so if you use my link, ignore the left half of the graph.)

Notice how the graph has no jumps in it (so the function is continuous). However, as you approach x = 0 from the right, something unusual happens–the graph starts oscillating between y = -1 and y = 1 faster and faster and faster (in fact, before you get to 0, the graph oscillates infinitely many times). This sort of odd behavior towards the edge of the domain is exactly what prevents a continuous function from being uniformly continuous.

Note also that lim x->0+ [sin (1/x)] does not exist. This is not an accident. *Any* function which is continuous but not uniformly continuous *must* have one of the limits of the function as you approach the edge of an interval fail to exist. (Note that having a limit be ∞ or -∞ also counts as the limit failing to exist.)

One more example: Consider the function f: (-∞, ∞) -> R defined by f(x) = x^2. (I assume that you are quite familar with the graph of this function.) Again, note that as we move towards the edge of the domain (in this case, towards x = -∞ or towards x = ∞), the function grows faster and faster and faster. So this function is also continuous but not uniformly continuous.

Again, note that lim x->-∞ [x^2] and lim x->∞ [x^2] both fail to exist (they’re ∞).

Some more comments to help illustrate the difference:

* The only condition uniform continuity really adds to continuity is that the behavior towards the edge of the domain does not involve ever-more-rapid changes in the value of the function. (Any continuous function is automatically uniformly continuous on any closed interval [a, b] which is a subset of its domain; it really is only at the very edge of an open interval that you can mess up uniform continuity in any way other than a jump in the graph.)
* As a special case of the previous comment: Any continuous function f: [a, b] -> R is automatically uniformly continuous. (Only functions where at least one side of the interval is open, or where one side of the interval is ∞ or -∞, can be continuous but not uniformly continuous.)
* A function with a bounded derivative (so that the function is continuous, and its value never rises or falls more quickly than at some fixed rate) is automatically uniformly continuous.

Note that all of the comments I’ve made are just to provide you with an idea of what „uniform continuity“ means; they’re not necessarily all exactly equivalent to it. As usual in math, if you’re trying to decide whether something is uniformly continuous or not, you should see whether it satisfies the definition. (But perhaps some of my ideas might allow you to make a more educated guess as to whether a function is uniformly continuous.)

The idea of uniform continuity is important because there are many theorems about uniformly continuous functions; so if you can prove that a function is uniformly continuous, then you already know a great deal about it (much more than you would know if you just knew it to be continuous). These theorems might allow you to compute integrals or derivatives more easily in certain situations, for example, either of which has an immense number of real-world applications.

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